What is the answer to ln(2x)-5ln(x^2)=0 ?

The answer to ln(2x)-5ln(x^2)=0 is x=e^{(ln(2))/9}

Solve for x: ln(2x)-5ln(x^2)=0

The solution is x=e^{(ln(2))/9}

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ln (2 x) - 5 ln (x^{2}) = 0

x = e^{\frac{l n ( 2 )}{9}}

Decimal Notation

x = 1.08005 \dots

Solution steps

ln (2 x) - 5 ln (x^{2}) = 0

Apply log rules

x = e^{\frac{l n ( 2 )}{9}}

Verify Solutions:

x = e^{\frac{l n ( 2 )}{9}}

True

The solution is

x = e^{\frac{l n ( 2 )}{9}}

1 - lo g_{10} (w - 7) = 0

lo g_{10} (x) 7 = - 2

2 = lo g_{e} (x)

x, ln (x - y) = 1

lo g_{10} (a) = 2.952

What is the answer to ln(2x)-5ln(x^2)=0 ?
The answer to ln(2x)-5ln(x^2)=0 is x=e^{(ln(2))/9}
Solve for x: ln(2x)-5ln(x^2)=0
The solution is x=e^{(ln(2))/9}