What is the answer to log_{3}(x+7)=2+log_{3}(x-1) ?

The answer to log_{3}(x+7)=2+log_{3}(x-1) is x=2

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log_{3}(x+7)=2+log_{3}(x-1)

lo g_{3} (x + 7) = 2 + lo g_{3} (x - 1)

x = 2

Solution steps

lo g_{3} (x + 7) = 2 + lo g_{3} (x - 1)

Apply log rules

x + 7 = 9 (x - 1)

Solve

x + 7 = 9 (x - 1) : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{6} (8 x) - 3 lo g_{6} (5) = 0

2 ln (4 x) = - 2

ln (6 x) = ln (9) + 2 lo g_{10} (10)

5 lo g_{10} (u) = 0

lo g_{3} (y) - 4 = lo g_{3} (5)

What is the answer to log_{3}(x+7)=2+log_{3}(x-1) ?
The answer to log_{3}(x+7)=2+log_{3}(x-1) is x=2
Solve for x: log_{3}(x+7)=2+log_{3}(x-1)
The solution is x=2