What is the answer to 2ln(4x)=2+ln(9) ?

The answer to 2ln(4x)=2+ln(9) is x=(e^{(2+2ln(3))/2})/(4)

Solve for x: 2ln(4x)=2+ln(9)

The solution is x=(e^{(2+2ln(3))/2})/(4)

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2 ln (4 x) = 2 + ln (9)

x = \frac{e ^{\frac{2 + 2 l n ( 3 )}{2}}}{4}

Decimal Notation

x = 2.03871 \dots

Solution steps

2 ln (4 x) = 2 + ln (9)

Divide both sides by

2

ln (4 x) = \frac{2 + ln ( 9 )}{2}

Apply log rules

4 x = e^{\frac{2 + 2 l n ( 3 )}{2}}

Solve

4 x = e^{\frac{2 + 2 l n ( 3 )}{2}} : x = \frac{e ^{\frac{2 + 2 l n ( 3 )}{2}}}{4}

x = \frac{e ^{\frac{2 + 2 l n ( 3 )}{2}}}{4}

Verify Solutions:

x = \frac{e ^{\frac{2 + 2 l n ( 3 )}{2}}}{4}

True

The solution is

x = \frac{e ^{\frac{2 + 2 l n ( 3 )}{2}}}{4}

lo g_{10} (5) + lo g_{10} (x) = 1

ln (x) + ln (x - 10) = 3

ln (x) + ln (x - 10) = 1

lo g_{10} (2 x + 4) = 2, x

- ln (x) + 2 = 0

What is the answer to 2ln(4x)=2+ln(9) ?
The answer to 2ln(4x)=2+ln(9) is x=(e^{(2+2ln(3))/2})/(4)
Solve for x: 2ln(4x)=2+ln(9)
The solution is x=(e^{(2+2ln(3))/2})/(4)