What is the answer to solvefor x,ln(x)+ln(x+1)=0 ?

The answer to solvefor x,ln(x)+ln(x+1)=0 is x=(-1+sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,ln(x)+ln(x+1)=0

solve for

x, ln (x) + ln (x + 1) = 0

x = \frac{- 1 + 5}{2}

Decimal Notation

x = 0.61803 \dots

Solution steps

ln (x) + ln (x + 1) = 0

Apply log rules

x (x + 1) = 1

Solve

x (x + 1) = 1 : x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

Verify Solutions:

x = \frac{- 1 + 5}{2}

True

, x = \frac{- 1 - 5}{2}

False

The solution is

x = \frac{- 1 + 5}{2}

lo g_{2} (2 x) = lo g_{4} (x)

lo g_{e} (lo g_{e} (x)) = 1

270 = 93 lo g_{10} (d) + 63

0.765 = - lo g_{10} (x)

lo g_{3} (x) + 2 lo g_{x} (9) = 5

What is the answer to solvefor x,ln(x)+ln(x+1)=0 ?
The answer to solvefor x,ln(x)+ln(x+1)=0 is x=(-1+sqrt(5))/2