What are the solutions to the equation 5x^2-4x-12=0 ?

The solutions to the equation 5x^2-4x-12=0 are x=2,x=-6/5

Find the zeros of 5x^2-4x-12=0

The zeros of 5x^2-4x-12=0 are x=2,x=-6/5

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5 x^{2} - 4 x - 12 = 0

x = 2, x = - \frac{6}{5}

Decimal Notation

x = 2, x = - 1.2

Solution steps

5 x^{2} - 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 12 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 12) = 16

x_{1, 2} = \frac{- ( - 4 ) \pm 16}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 16}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 16}{2 \cdot 5}

x = \frac{- ( - 4 ) + 16}{2 \cdot 5} : 2

x = \frac{- ( - 4 ) - 16}{2 \cdot 5} : - \frac{6}{5}

The solutions to the quadratic equation are:

x = 2, x = - \frac{6}{5}

(e^{- \frac{x}{2}})^{2}

2 n^{2} - 4 n - 14 = 0

- 4 i^{2}

- 2 x + 1 = - x + 8

3 x - 15

What are the solutions to the equation 5x^2-4x-12=0 ?
The solutions to the equation 5x^2-4x-12=0 are x=2,x=-6/5
Find the zeros of 5x^2-4x-12=0
The zeros of 5x^2-4x-12=0 are x=2,x=-6/5