What is the answer to 2x^2=(x^2)/(ln(x)) ?

The answer to 2x^2=(x^2)/(ln(x)) is x=sqrt(e)

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2x^2=(x^2)/(ln(x))

2 x^{2} = \frac{x ^{2}}{ln ( x )}

x = e

Decimal Notation

x = 1.64872 \dots

Solution steps

2 x^{2} = \frac{x ^{2}}{ln ( x )}

Multiply both sides by

ln (x)

2 x^{2} ln (x) = x^{2}

Divide both sides by

2 x^{2}

ln (x) = \frac{1}{2}

Apply log rules

x = e

Verify Solutions:

x = e

True

The solution is

x = e

ln (x^{2}) = 4 ln (x)

lo g_{100} (x) = \frac{3}{2}

0.21 = ln (y)

lo g_{4} (2 x + 5) - lo g_{4} (3 - x) = 2

x, ln (x) + 2 ln (y) = c

What is the answer to 2x^2=(x^2)/(ln(x)) ?
The answer to 2x^2=(x^2)/(ln(x)) is x=sqrt(e)
Solve for x: 2x^2=(x^2)/(ln(x))
The solution is x=sqrt(e)