What is the answer to log_{2}(x^2-3x-2)=4 ?

The answer to log_{2}(x^2-3x-2)=4 is x=6,x=-3

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log_{2}(x^2-3x-2)=4

lo g_{2} (x^{2} - 3 x - 2) = 4

x = 6, x = - 3

Solution steps

lo g_{2} (x^{2} - 3 x - 2) = 4

Apply log rules

x^{2} - 3 x - 2 = 16

Solve

x^{2} - 3 x - 2 = 16 : x = 6, x = - 3

x = 6, x = - 3

x - 3 + 2 ln (x) = 0

x, lo g_{10} (2 x + 1) = 2

lo g_{2} (x + 1) + lo g_{2} (x + 1) = 3

3 lo g_{10} (x - 2) = 10

lo g_{5} (x) = 25

What is the answer to log_{2}(x^2-3x-2)=4 ?
The answer to log_{2}(x^2-3x-2)=4 is x=6,x=-3
Solve for x: log_{2}(x^2-3x-2)=4
The solution is x=6,x=-3