What is the answer to 4.9=log_{10}(a/(a^0)) ?

The answer to 4.9=log_{10}(a/(a^0)) is a=10^{4.9}

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4.9=log_{10}(a/(a^0))

4.9 = lo g_{10} (\frac{a}{a ^{0}})

a = 1 0^{4.9}

Decimal Notation

a = 79432.82347 \dots

Solution steps

4.9 = lo g_{10} (\frac{a}{a ^{0}})

Apply log rules

1 0^{4.9} = a

Switch sides

a = 1 0^{4.9}

lo g_{36} (N) = - \frac{3}{2}

lo g_{2} (5 x + 6) = 4

lo g_{10} (x - 1) = 2 lo g_{10} (x) - 1

3 lo g_{e} (t) = 5

lo g_{10} (3 x^{3}) = 8

What is the answer to 4.9=log_{10}(a/(a^0)) ?
The answer to 4.9=log_{10}(a/(a^0)) is a=10^{4.9}
Solve for a: 4.9=log_{10}(a/(a^0))
The solution is a=10^{4.9}