What is the answer to log_{5}(2x+1)=1-log_{5}(2) ?

The answer to log_{5}(2x+1)=1-log_{5}(2) is x= 3/4

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log_{5}(2x+1)=1-log_{5}(2)

lo g_{5} (2 x + 1) = 1 - lo g_{5} (2)

x = \frac{3}{4}

Decimal Notation

x = 0.75

Solution steps

lo g_{5} (2 x + 1) = 1 - lo g_{5} (2)

Apply log rules

2 x + 1 = \frac{5}{2}

Solve

2 x + 1 = \frac{5}{2} : x = \frac{3}{4}

x = \frac{3}{4}

lo g_{x} (8) = 4

x, lo g_{3} (m x) = c

2.53 = ln (\frac{X}{25})

lo g_{3} (x) = 64 lo g_{x} (3)

lo g_{2} (x) = 4 - lo g_{x} (2)

What is the answer to log_{5}(2x+1)=1-log_{5}(2) ?
The answer to log_{5}(2x+1)=1-log_{5}(2) is x= 3/4
Solve for x: log_{5}(2x+1)=1-log_{5}(2)
The solution is x= 3/4