What is the answer to log_{5}(x+15)-log_{5}(x-9)=2 ?

The answer to log_{5}(x+15)-log_{5}(x-9)=2 is x=10

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log_{5}(x+15)-log_{5}(x-9)=2

lo g_{5} (x + 15) - lo g_{5} (x - 9) = 2

x = 10

Solution steps

lo g_{5} (x + 15) - lo g_{5} (x - 9) = 2

Add

lo g_{5} (x - 9)

to both sides

lo g_{5} (x + 15) - lo g_{5} (x - 9) + lo g_{5} (x - 9) = 2 + lo g_{5} (x - 9)

Simplify

lo g_{5} (x + 15) = 2 + lo g_{5} (x - 9)

Apply log rules

x + 15 = 25 (x - 9)

Solve

x + 15 = 25 (x - 9) : x = 10

x = 10

Verify Solutions:

x = 10

True

The solution is

x = 10

lo g_{10} (4) + lo g_{10} (w) = 2

lo g_{2} (x + 6) - lo g_{2} (x - 8) = 3

lo g_{7} (2 x + 5) = lo g_{7} (x - 3)

9 lo g_{6} (5 w + 6) + 3 = 30

lo g_{3} (x) + lo g_{3} (2) = 5

What is the answer to log_{5}(x+15)-log_{5}(x-9)=2 ?
The answer to log_{5}(x+15)-log_{5}(x-9)=2 is x=10
Solve for x: log_{5}(x+15)-log_{5}(x-9)=2
The solution is x=10