What is the answer to log_{2}(7x)+3log_{2}(3)=5 ?

The answer to log_{2}(7x)+3log_{2}(3)=5 is x= 32/189

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(7x)+3log_{2}(3)=5

lo g_{2} (7 x) + 3 lo g_{2} (3) = 5

x = \frac{32}{189}

Decimal Notation

x = 0.16931 \dots

Solution steps

lo g_{2} (7 x) + 3 lo g_{2} (3) = 5

Move

3 lo g_{2} (3)

to the right side

lo g_{2} (7 x) = 5 - 3 lo g_{2} (3)

Apply log rules

7 x = \frac{32}{27}

Solve

7 x = \frac{32}{27} : x = \frac{32}{189}

x = \frac{32}{189}

Verify Solutions:

x = \frac{32}{189}

True

The solution is

x = \frac{32}{189}

3 = lo g_{10} (\frac{1 0 ^{5}}{x})

0.85 = lo g_{10} (x)

2 lo g_{10} (2 - x) = - x

lo g_{6} (N) = 2

ln (\frac{3 x + 2}{2}) = - 1

What is the answer to log_{2}(7x)+3log_{2}(3)=5 ?
The answer to log_{2}(7x)+3log_{2}(3)=5 is x= 32/189
Solve for x: log_{2}(7x)+3log_{2}(3)=5
The solution is x= 32/189