What is the answer to ln(x^2-x)=ln(6) ?

The answer to ln(x^2-x)=ln(6) is x=3,x=-2

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ln(x^2-x)=ln(6)

ln (x^{2} - x) = ln (6)

x = 3, x = - 2

Solution steps

ln (x^{2} - x) = ln (6)

Apply log rules

x^{2} - x = 6

Solve

x^{2} - x = 6 : x = 3, x = - 2

x = 3, x = - 2

Verify Solutions:

x = 3

True

, x = - 2

True

The solutions are

x = 3, x = - 2

ln (x + 1) x = 0

- 1 + lo g_{3} (- 5 x + x^{2} - 62) = 3

ln (t) = 1

10 \cdot lo g_{10} (x) = 46.7

b, c = lo g_{35} (b)

What is the answer to ln(x^2-x)=ln(6) ?
The answer to ln(x^2-x)=ln(6) is x=3,x=-2
Solve for x: ln(x^2-x)=ln(6)
The solution is x=3,x=-2