What is the answer to log_{2}(x^2-2x)-3=0 ?

The answer to log_{2}(x^2-2x)-3=0 is x=4,x=-2

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log_{2}(x^2-2x)-3=0

lo g_{2} (x^{2} - 2 x) - 3 = 0

x = 4, x = - 2

Solution steps

lo g_{2} (x^{2} - 2 x) - 3 = 0

Move

3

to the right side

lo g_{2} (x^{2} - 2 x) = 3

Apply log rules

x^{2} - 2 x = 8

Solve

x^{2} - 2 x = 8 : x = 4, x = - 2

x = 4, x = - 2

Verify Solutions:

x = 4

True

, x = - 2

True

The solutions are

x = 4, x = - 2

12 + 2 ln (x) = 14

lo g_{2} (x^{2} + 3 x - 2) = 3

lo g_{2} (5 x - 1) = 2

lo g_{8} (x) - lo g_{x} (64) = 1

\frac{ln ( x )}{x} = 3

What is the answer to log_{2}(x^2-2x)-3=0 ?
The answer to log_{2}(x^2-2x)-3=0 is x=4,x=-2
Solve for x: log_{2}(x^2-2x)-3=0
The solution is x=4,x=-2