What are the solutions to the equation (7x+3)^2=4 ?

The solutions to the equation (7x+3)^2=4 are x=-1/7 ,x=-5/7

Find the zeros of (7x+3)^2=4

The zeros of (7x+3)^2=4 are x=-1/7 ,x=-5/7

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(7 x + 3)^{2} = 4

x = - \frac{1}{7}, x = - \frac{5}{7}

Solution steps

(7 x + 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 x + 3 = 4 : x = - \frac{1}{7}

Solve

7 x + 3 = - 4 : x = - \frac{5}{7}

The solutions to the quadratic equation are:

x = - \frac{1}{7}, x = - \frac{5}{7}

x - 3 < 4

2 x^{2} + 2 y^{2}

x^{2} + x < 2

\frac{1}{1 + \frac{1}{\frac{7}{2} - 3}}

∣ x - 7 ∣ = ∣ 3 x + 8 ∣

What are the solutions to the equation (7x+3)^2=4 ?
The solutions to the equation (7x+3)^2=4 are x=-1/7 ,x=-5/7
Find the zeros of (7x+3)^2=4
The zeros of (7x+3)^2=4 are x=-1/7 ,x=-5/7