What is the answer to ln(2)+ln(x)=5 ?

The answer to ln(2)+ln(x)=5 is x=(e^5)/2

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ln(2)+ln(x)=5

ln (2) + ln (x) = 5

x = \frac{e ^{5}}{2}

Decimal Notation

x = 74.20657 \dots

Solution steps

ln (2) + ln (x) = 5

Move

ln (2)

to the right side

ln (x) = 5 - ln (2)

Apply log rules

x = \frac{e ^{5}}{2}

Verify Solutions:

x = \frac{e ^{5}}{2}

True

The solution is

x = \frac{e ^{5}}{2}

5 lo g_{4} (64 k) = 18

lo g_{5} (x) + 2 lo g_{x} (5) = 3

lo g_{e} (2 x) = 1

lo g_{e} (2 x) = 2

lo g_{x + 2} (3 x^{2} - 12) = 2