What is the answer to 2log_{3}(x)-log_{3}(x+4)=2 ?

The answer to 2log_{3}(x)-log_{3}(x+4)=2 is x=12

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2log_{3}(x)-log_{3}(x+4)=2

2 lo g_{3} (x) - lo g_{3} (x + 4) = 2

x = 12

Solution steps

2 lo g_{3} (x) - lo g_{3} (x + 4) = 2

Apply log rules

x^{2} = 9 (x + 4)

Solve

x^{2} = 9 (x + 4) : x = 12, x = - 3

x = 12, x = - 3

Verify Solutions:

x = 12

True

, x = - 3

False

The solution is

x = 12

lo g_{10} (x - 3) = 1

0.26 = ln (x)

ln (20 C) = ln (5)

x, ln ((x + 1)^{2}) = 2

lo g_{t} (2) + lo g_{t} (4) = 1

What is the answer to 2log_{3}(x)-log_{3}(x+4)=2 ?
The answer to 2log_{3}(x)-log_{3}(x+4)=2 is x=12
Solve for x: 2log_{3}(x)-log_{3}(x+4)=2
The solution is x=12