What is the answer to solvefor x,log_{4}(x-2y)=0 ?

The answer to solvefor x,log_{4}(x-2y)=0 is x=1+2y

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solvefor x,log_{4}(x-2y)=0

solve for

x, lo g_{4} (x - 2 y) = 0

x = 1 + 2 y

Solution steps

lo g_{4} (x - 2 y) = 0

Apply log rules

x - 2 y = 1

Solve

x - 2 y = 1 : x = 1 + 2 y

x = 1 + 2 y

lo g_{10} (2 x) = 0.8821

ln (- x) = x

ln (3 x - 5) + ln (3 x - 7) = 3 ln (2)

0.51 = lo g_{10} (x)

lo g_{6} (3 x + 2) + lo g_{6} (x - 5) = 1

What is the answer to solvefor x,log_{4}(x-2y)=0 ?
The answer to solvefor x,log_{4}(x-2y)=0 is x=1+2y