What is the answer to log_{2}(x-5)+log_{2}(x-5)=2 ?

The answer to log_{2}(x-5)+log_{2}(x-5)=2 is x=7

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log_{2}(x-5)+log_{2}(x-5)=2

lo g_{2} (x - 5) + lo g_{2} (x - 5) = 2

x = 7

Solution steps

lo g_{2} (x - 5) + lo g_{2} (x - 5) = 2

Add similar elements:

lo g_{2} (x - 5) + lo g_{2} (x - 5) = 2 lo g_{2} (x - 5)

2 lo g_{2} (x - 5) = 2

Divide both sides by

2

lo g_{2} (x - 5) = 1

Apply log rules

x - 5 = 2

Solve

x - 5 = 2 : x = 7

x = 7

Verify Solutions:

x = 7

True

The solution is

x = 7

lo g_{2} (n) = 4

ln (x) + ln (x + 2) = ln (15)

lo g_{4} (x) = 2 + lo g_{4} (2)

16.04 = 10 \cdot lo g_{10} (x)

lo g_{10} (x + 1) = - 1

What is the answer to log_{2}(x-5)+log_{2}(x-5)=2 ?
The answer to log_{2}(x-5)+log_{2}(x-5)=2 is x=7
Solve for x: log_{2}(x-5)+log_{2}(x-5)=2
The solution is x=7