What is the answer to log_{3}(x-2)-log_{9}(x-4)=1 ?

The answer to log_{3}(x-2)-log_{9}(x-4)=1 is x=8,x=5

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log_{3}(x-2)-log_{9}(x-4)=1

lo g_{3} (x - 2) - lo g_{9} (x - 4) = 1

x = 8, x = 5

Solution steps

lo g_{3} (x - 2) - lo g_{9} (x - 4) = 1

Apply log rules

(x - 2)^{2} = 9 (x - 4)

Solve

(x - 2)^{2} = 9 (x - 4) : x = 8, x = 5

x = 8, x = 5

Verify Solutions:

x = 8

True

, x = 5

True

The solutions are

x = 8, x = 5

4 + 9 \cdot ln (x) = 15.8

lo g_{2} (x^{7}) = 28

5 lo g_{2} (x) = lo g_{2} (x)

ln (7 x) = - 1

y, x = ln (\frac{x}{y})

What is the answer to log_{3}(x-2)-log_{9}(x-4)=1 ?
The answer to log_{3}(x-2)-log_{9}(x-4)=1 is x=8,x=5
Solve for x: log_{3}(x-2)-log_{9}(x-4)=1
The solution is x=8,x=5