What is the answer to log_{10}(6x)=-log_{10}(3x) ?

The answer to log_{10}(6x)=-log_{10}(3x) is x= 1/(10^{(log_{10)(18))/2}}

Solve for x: log_{10}(6x)=-log_{10}(3x)

The solution is x= 1/(10^{(log_{10)(18))/2}}

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lo g_{10} (6 x) = - lo g_{10} (3 x)

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 18 )}{2}}}

Decimal Notation

x = 0.23570 \dots

Solution steps

lo g_{10} (6 x) = - lo g_{10} (3 x)

Apply log rules

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 18 )}{2}}}

Verify Solutions:

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 18 )}{2}}}

True

The solution is

x = \frac{1}{1 0 ^{\frac{l o g _{10} ( 18 )}{2}}}

lo g_{3} (9 x + 2) = 4

lo g_{2^{2}} (x^{2}) = 8

x, 0 = lo g_{10} (x + h)

2 lo g_{3} (x) = 4 lo g_{3} (8)

ln (\frac{t - 64}{125}) = - 0.07 t

What is the answer to log_{10}(6x)=-log_{10}(3x) ?
The answer to log_{10}(6x)=-log_{10}(3x) is x= 1/(10^{(log_{10)(18))/2}}
Solve for x: log_{10}(6x)=-log_{10}(3x)
The solution is x= 1/(10^{(log_{10)(18))/2}}