en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7<= 8x+3<19

Solution

7 \leq 8 x + 3 < 19

Solution

\frac{1}{2} \leq x < 2

+2

Interval Notation

[\frac{1}{2}, 2)

Decimal Notation

0.5 \leq x < 2

Solution steps

7 \leq 8 x + 3 < 19

If

a \leq u < b

then

a \leq u and u < b

7 \leq 8 x + 3 and 8 x + 3 < 19

7 \leq 8 x + 3 : x \geq \frac{1}{2}

8 x + 3 < 19 : x < 2

Combine the intervals

x \geq \frac{1}{2} and x < 2

Merge Overlapping Intervals

\frac{1}{2} \leq x < 2

Popular Examples

factor 16+8x+x^2 factor

16 + 8 x + x^{2}

2 x + 15 = 3 x + 1

factor 9-x^2 factor

9 - x^{2}

simplify (4^3)/(3^3)simplify

\frac{4 ^{3}}{3 ^{3}}

15=|(11s-8)/(5s+1)|

15 = \frac{11 s - 8}{5 s + 1}

Frequently Asked Questions (FAQ)

What is 7<= 8x+3<19 ?
The solution to 7<= 8x+3<19 is 1/2 <= x<2