What is the answer to ln(x/(x^2+1))=1 ?

The answer to ln(x/(x^2+1))=1 is No Solution for x\in\mathbb{R}

Solve for x: ln(x/(x^2+1))=1

The solution is No Solution for x\in\mathbb{R}

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ln (\frac{x}{x ^{2} + 1}) = 1

No Solution for x \in R

Solution steps

ln (\frac{x}{x ^{2} + 1}) = 1

Apply log rules

\frac{x}{x ^{2} + 1} = e^{1}

Multiply both sides by

x^{2} + 1

\frac{x}{x ^{2} + 1} (x^{2} + 1) = e^{1} (x^{2} + 1)

Simplify

x = e (x^{2} + 1)

Solve

x = e (x^{2} + 1) :

No Solution for

x \in R

No Solution for x \in R

lo g_{2} (x) + 3 lo g_{10} (x) + 2 = 0

ln (x + 4) + ln (x - 2) = 2 ln (x)

lo g_{10} (x) = \frac{1}{x}

lo g_{2} (x) - 2 lo g_{x} (3) = 0

ln (5 x - 6) = 3

What is the answer to ln(x/(x^2+1))=1 ?
The answer to ln(x/(x^2+1))=1 is No Solution for x\in\mathbb{R}
Solve for x: ln(x/(x^2+1))=1
The solution is No Solution for x\in\mathbb{R}