What is the answer to (ln(x))^2=4 ?

The answer to (ln(x))^2=4 is x=e^2,x= 1/(e^2)

Solve for x: (ln(x))^2=4

The solution is x=e^2,x= 1/(e^2)

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(ln (x))^{2} = 4

x = e^{2}, x = \frac{1}{e ^{2}}

Decimal Notation

x = 7.38905 \dots, x = 0.13533 \dots

Solution steps

(ln (x))^{2} = 4

Rewrite the equation with

ln (x) = u

(u)^{2} = 4

Solve

u^{2} = 4 : u = 4, u = - 4

u = 4, u = - 4

Substitute back

u = ln (x),

solve for

x

Solve

ln (x) = 4 : x = e^{2}

Solve

ln (x) = - 4 : x = \frac{1}{e ^{2}}

x = e^{2}, x = \frac{1}{e ^{2}}

Verify Solutions:

x = e^{2}

True

, x = \frac{1}{e ^{2}}

True

The solutions are

x = e^{2}, x = \frac{1}{e ^{2}}

(ln (x))^{2} = 1

lo g_{2} (- x - 1) = 1

\frac{n}{2 ^{k}} = ln (x)

lo g_{2} (x) = 1.5

lo g_{10} (3 x - 2) = 3

What is the answer to (ln(x))^2=4 ?
The answer to (ln(x))^2=4 is x=e^2,x= 1/(e^2)
Solve for x: (ln(x))^2=4
The solution is x=e^2,x= 1/(e^2)