What is the answer to ln(x^{1/2}-4)=3 ?

The answer to ln(x^{1/2}-4)=3 is x=e^6+8e^3+16

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ln(x^{1/2}-4)=3

ln (x^{\frac{1}{2}} - 4) = 3

x = e^{6} + 8 e^{3} + 16

Decimal Notation

x = 580.11308 \dots

Solution steps

ln (x^{\frac{1}{2}} - 4) = 3

Apply log rules

x^{\frac{1}{2}} - 4 = e^{3}

Solve

x^{\frac{1}{2}} - 4 = e^{3} : x = e^{6} + 8 e^{3} + 16

x = e^{6} + 8 e^{3} + 16

4 ln (- 8 x - 2) - 9 = 8

lo g_{2} (\frac{3 x + 1}{2 x - 7}) = 3

lo g_{2} (x) = 0.3

10 0^{l o g_{10} (x)} = 2 x^{3}

ln (x) + ln (2 x - 11) = ln (21)

What is the answer to ln(x^{1/2}-4)=3 ?
The answer to ln(x^{1/2}-4)=3 is x=e^6+8e^3+16
Solve for x: ln(x^{1/2}-4)=3
The solution is x=e^6+8e^3+16