What is the answer to log_{10}(5x^2+13x-5)=0 ?

The answer to log_{10}(5x^2+13x-5)=0 is x= 2/5 ,x=-3

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log_{10}(5x^2+13x-5)=0

lo g_{10} (5 x^{2} + 13 x - 5) = 0

x = \frac{2}{5}, x = - 3

Decimal Notation

x = 0.4, x = - 3

Solution steps

lo g_{10} (5 x^{2} + 13 x - 5) = 0

Apply log rules

5 x^{2} + 13 x - 5 = 1

Solve

5 x^{2} + 13 x - 5 = 1 : x = \frac{2}{5}, x = - 3

x = \frac{2}{5}, x = - 3

4 lo g_{3} (- 5 x) = 8

lo g_{10} (x) = 0.41

lo g_{10} (x) = 0.34

lo g_{10} (x) = 0.33

lo g_{10} (x) = 0.25

What is the answer to log_{10}(5x^2+13x-5)=0 ?
The answer to log_{10}(5x^2+13x-5)=0 is x= 2/5 ,x=-3
Solve for x: log_{10}(5x^2+13x-5)=0
The solution is x= 2/5 ,x=-3