What is the answer to 14=-log_{10}(x) ?

The answer to 14=-log_{10}(x) is x= 1/(10^{14)}

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14=-log_{10}(x)

14 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{14}}

Decimal Notation

x = 1.0 E - 14

Solution steps

14 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

14 + lo g_{10} (x) = 0

Move

14

to the right side

lo g_{10} (x) = - 14

Apply log rules

x = \frac{1}{1 0 ^{14}}

Verify Solutions:

x = \frac{1}{1 0 ^{14}}

True

The solution is

x = \frac{1}{1 0 ^{14}}

lo g_{6} (x) - lo g_{6} (x - 1) = 1

lo g_{3} (x) + 2 = 3 lo g_{x} (3)

lo g_{2} (x) + lo g_{x} (8) = 4

lo g_{5} (x + 3) - lo g_{5} (x) = 1

x, 44 f = ln (x^{2} - 2 x)

What is the answer to 14=-log_{10}(x) ?
The answer to 14=-log_{10}(x) is x= 1/(10^{14)}
Solve for x: 14=-log_{10}(x)
The solution is x= 1/(10^{14)}