What is the answer to log_{2}(x+7)+log_{2}(x-7)=5 ?

The answer to log_{2}(x+7)+log_{2}(x-7)=5 is x=9

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log_{2}(x+7)+log_{2}(x-7)=5

lo g_{2} (x + 7) + lo g_{2} (x - 7) = 5

x = 9

Solution steps

lo g_{2} (x + 7) + lo g_{2} (x - 7) = 5

Apply log rules

(x + 7) (x - 7) = 32

Solve

(x + 7) (x - 7) = 32 : x = 9, x = - 9

x = 9, x = - 9

Verify Solutions:

x = 9

True

, x = - 9

False

The solution is

x = 9

5 ln (3 x - 4) = 30

3^{l o g_{3} (3 x + 4)} = 3 x

15 = 10 \cdot lo g_{10} (x)

ln (3 x - 18) = 4

x, z = ln (x^{2} + y)

What is the answer to log_{2}(x+7)+log_{2}(x-7)=5 ?
The answer to log_{2}(x+7)+log_{2}(x-7)=5 is x=9
Solve for x: log_{2}(x+7)+log_{2}(x-7)=5
The solution is x=9