What is the answer to log_{10}(x)(81)=4 ?

The answer to log_{10}(x)(81)=4 is x=10^{4/81}

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log_{10}(x)(81)=4

lo g_{10} (x) (81) = 4

x = 1 0^{\frac{4}{81}}

Decimal Notation

x = 1.12042 \dots

Solution steps

lo g_{10} (x) (81) = 4

Divide both sides by

81

lo g_{10} (x) = \frac{4}{81}

Apply log rules

x = 1 0^{\frac{4}{81}}

Verify Solutions:

x = 1 0^{\frac{4}{81}}

True

The solution is

x = 1 0^{\frac{4}{81}}

3 ln (6 x) = - 3

a, lo g_{10} (a^{2} b) = 1

lo g_{3} (- 4 x + 7) = 3

ln (x) = 1.5017800000000 \dots

lo g_{x} (5) = 1

What is the answer to log_{10}(x)(81)=4 ?
The answer to log_{10}(x)(81)=4 is x=10^{4/81}
Solve for x: log_{10}(x)(81)=4
The solution is x=10^{4/81}