What is the answer to log_{2}(log_{3}(2x-1))=2 ?

The answer to log_{2}(log_{3}(2x-1))=2 is x=41

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log_{2}(log_{3}(2x-1))=2

lo g_{2} (lo g_{3} (2 x - 1)) = 2

x = 41

Solution steps

lo g_{2} (lo g_{3} (2 x - 1)) = 2

Apply log rules

2 x - 1 = 81

Solve

2 x - 1 = 81 : x = 41

x = 41

Verify Solutions:

x = 41

True

The solution is

x = 41

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What is the answer to log_{2}(log_{3}(2x-1))=2 ?
The answer to log_{2}(log_{3}(2x-1))=2 is x=41
Solve for x: log_{2}(log_{3}(2x-1))=2
The solution is x=41