What is the answer to log_{7}(2x)+log_{7}(2)=5 ?

The answer to log_{7}(2x)+log_{7}(2)=5 is x= 16807/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{7}(2x)+log_{7}(2)=5

lo g_{7} (2 x) + lo g_{7} (2) = 5

x = \frac{16807}{4}

Solution steps

lo g_{7} (2 x) + lo g_{7} (2) = 5

Move

lo g_{7} (2)

to the right side

lo g_{7} (2 x) = 5 - lo g_{7} (2)

Apply log rules

2 x = \frac{16807}{2}

Solve

2 x = \frac{16807}{2} : x = \frac{16807}{4}

x = \frac{16807}{4}

Verify Solutions:

x = \frac{16807}{4}

True

The solution is

x = \frac{16807}{4}

2 ln (x - 1) + ln (x + 7) = 3 ln (x)

lo g_{4} (\frac{1}{2} x + 1) = 3.2

lo g_{10} (x) = 5.48

lo g_{3} (x^{3}) - lo g_{3} (9 x) = 2

lo g_{10} (2 x + 2) = 2

What is the answer to log_{7}(2x)+log_{7}(2)=5 ?
The answer to log_{7}(2x)+log_{7}(2)=5 is x= 16807/4
Solve for x: log_{7}(2x)+log_{7}(2)=5
The solution is x= 16807/4