What is the answer to log_{3}(x+1)-log_{3}(x)=1 ?

The answer to log_{3}(x+1)-log_{3}(x)=1 is x= 1/2

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log_{3}(x+1)-log_{3}(x)=1

lo g_{3} (x + 1) - lo g_{3} (x) = 1

x = \frac{1}{2}

Solution steps

lo g_{3} (x + 1) - lo g_{3} (x) = 1

Add

lo g_{3} (x)

to both sides

lo g_{3} (x + 1) - lo g_{3} (x) + lo g_{3} (x) = 1 + lo g_{3} (x)

Simplify

lo g_{3} (x + 1) = 1 + lo g_{3} (x)

Apply log rules

x + 1 = 3 x

Solve

x + 1 = 3 x : x = \frac{1}{2}

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

The solution is

x = \frac{1}{2}

2 + ln (x) = 5

lo g_{25} (x) = 1

x, lo g_{10} (x) = 3

x, lo g_{10} (x) = 2

x, lo g_{10} (x) = 0

What is the answer to log_{3}(x+1)-log_{3}(x)=1 ?
The answer to log_{3}(x+1)-log_{3}(x)=1 is x= 1/2
Solve for x: log_{3}(x+1)-log_{3}(x)=1
The solution is x= 1/2