What is the answer to ln(2x)-3ln(x^2)=0 ?

The answer to ln(2x)-3ln(x^2)=0 is x=e^{(ln(2))/5}

Solve for x: ln(2x)-3ln(x^2)=0

The solution is x=e^{(ln(2))/5}

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ln (2 x) - 3 ln (x^{2}) = 0

x = e^{\frac{l n ( 2 )}{5}}

Decimal Notation

x = 1.14869 \dots

Solution steps

ln (2 x) - 3 ln (x^{2}) = 0

Apply log rules

x = e^{\frac{l n ( 2 )}{5}}

Verify Solutions:

x = e^{\frac{l n ( 2 )}{5}}

True

The solution is

x = e^{\frac{l n ( 2 )}{5}}

lo g_{10} (x + 2) = 5

lo g_{10} (x + 2) = 1

0.4 = lo g_{2} (\frac{x}{32000})

ln (x) = \frac{1}{2} x - 2

4 lo g_{x} (2) = lo g_{2} (x)

What is the answer to ln(2x)-3ln(x^2)=0 ?
The answer to ln(2x)-3ln(x^2)=0 is x=e^{(ln(2))/5}
Solve for x: ln(2x)-3ln(x^2)=0
The solution is x=e^{(ln(2))/5}