What are the solutions to the equation -2x^2=-128 ?

The solutions to the equation -2x^2=-128 are x=8,x=-8

Find the zeros of -2x^2=-128

The zeros of -2x^2=-128 are x=8,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} = - 128

x = 8, x = - 8

Solution steps

- 2 x^{2} = - 128

Divide both sides by

- 2

x^{2} = 64

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 64, x = - 64

64 = 8

- 64 = - 8

x = 8, x = - 8

3 (x + 2)^{2} = 54

lo g_{2} (x) > 1

e^{\frac{iπ}{4}}

lo g_{5} (5^{4})

\frac{2}{5} (2 x - 1) > 10

What are the solutions to the equation -2x^2=-128 ?
The solutions to the equation -2x^2=-128 are x=8,x=-8
Find the zeros of -2x^2=-128
The zeros of -2x^2=-128 are x=8,x=-8