What is the answer to log_{5}(2x)+log_{5}(5)=4 ?

The answer to log_{5}(2x)+log_{5}(5)=4 is x= 125/2

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log_{5}(2x)+log_{5}(5)=4

lo g_{5} (2 x) + lo g_{5} (5) = 4

x = \frac{125}{2}

Solution steps

lo g_{5} (2 x) + lo g_{5} (5) = 4

Move

lo g_{5} (5)

to the right side

lo g_{5} (2 x) = 4 - lo g_{5} (5)

Apply log rules

2 x = 125

Solve

2 x = 125 : x = \frac{125}{2}

x = \frac{125}{2}

Verify Solutions:

x = \frac{125}{2}

True

The solution is

x = \frac{125}{2}

ln (x - 4) + ln (x + 1) = ln (x - 8)

lo g_{3} (x^{2}) = - 2

- 26 + lo g_{4} ((4 - x)^{7}) = 9

lo g_{10} (10 c) = 2

y, ln (y) = e^{x}

What is the answer to log_{5}(2x)+log_{5}(5)=4 ?
The answer to log_{5}(2x)+log_{5}(5)=4 is x= 125/2
Solve for x: log_{5}(2x)+log_{5}(5)=4
The solution is x= 125/2