What is the answer to log_{3}(x+5)+log_{3}(x-7)=2 ?

The answer to log_{3}(x+5)+log_{3}(x-7)=2 is x=1+3sqrt(5)

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log_{3}(x+5)+log_{3}(x-7)=2

lo g_{3} (x + 5) + lo g_{3} (x - 7) = 2

x = 1 + 35

Solution steps

lo g_{3} (x + 5) + lo g_{3} (x - 7) = 2

Apply log rules

(x + 5) (x - 7) = 9

Solve

(x + 5) (x - 7) = 9 : x = 1 + 35, x = 1 - 35

x = 1 + 35, x = 1 - 35

Verify Solutions:

x = 1 + 35

True

, x = 1 - 35

False

The solution is

x = 1 + 35

lo g_{e} (2 - 3 x) = 0

lo g_{9} (x^{9}) = 9

20 \cdot lo g_{10} (x^{2} - 15) = 0

y, x = lo g_{4} (y)

2 + 3 lo g_{12} (3 d) = 5

What is the answer to log_{3}(x+5)+log_{3}(x-7)=2 ?
The answer to log_{3}(x+5)+log_{3}(x-7)=2 is x=1+3sqrt(5)
Solve for x: log_{3}(x+5)+log_{3}(x-7)=2
The solution is x=1+3sqrt(5)