What is the answer to log_{10}(x)+log_{10}(80)=3 ?

The answer to log_{10}(x)+log_{10}(80)=3 is x= 25/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}(x)+log_{10}(80)=3

lo g_{10} (x) + lo g_{10} (80) = 3

x = \frac{25}{2}

Solution steps

lo g_{10} (x) + lo g_{10} (80) = 3

Move

lo g_{10} (80)

to the right side

lo g_{10} (x) = 3 - lo g_{10} (80)

Apply log rules

x = \frac{25}{2}

Verify Solutions:

x = \frac{25}{2}

True

The solution is

x = \frac{25}{2}

ln (x^{- 1}) = 3

x, ln (x) + ln (x) = 0

ln (3 x) = x

lo g_{x + 6} (2 x^{2} - 4 x) = 2

lo g_{2} (x + 1) + lo g_{2} (x - 2) = 3

What is the answer to log_{10}(x)+log_{10}(80)=3 ?
The answer to log_{10}(x)+log_{10}(80)=3 is x= 25/2
Solve for x: log_{10}(x)+log_{10}(80)=3
The solution is x= 25/2