What is the answer to log_{2}(2x+1)=-3 ?

The answer to log_{2}(2x+1)=-3 is x=-7/16

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log_{2}(2x+1)=-3

lo g_{2} (2 x + 1) = - 3

x = - \frac{7}{16}

Solution steps

lo g_{2} (2 x + 1) = - 3

Apply log rules

2 x + 1 = \frac{1}{8}

Solve

2 x + 1 = \frac{1}{8} : x = - \frac{7}{16}

x = - \frac{7}{16}

x, ln (x) = 1

ln (y^{2}) = ln (y + 3) + 2

x, y = ln (3 x)

x^{2} ln (x) - 9 ln (x) = 0

x, ln (x) = z

What is the answer to log_{2}(2x+1)=-3 ?
The answer to log_{2}(2x+1)=-3 is x=-7/16
Solve for x: log_{2}(2x+1)=-3
The solution is x=-7/16