What is the answer to log_{10}(5x)+log_{10}(x+5)=1 ?

The answer to log_{10}(5x)+log_{10}(x+5)=1 is x=(-5+sqrt(33))/2

Solve for x: log_{10}(5x)+log_{10}(x+5)=1

The solution is x=(-5+sqrt(33))/2

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lo g_{10} (5 x) + lo g_{10} (x + 5) = 1

x = \frac{- 5 + 33}{2}

Solution steps

lo g_{10} (5 x) + lo g_{10} (x + 5) = 1

Apply log rules

5 x (x + 5) = 10

Solve

5 x (x + 5) = 10 : x = \frac{- 5 + 33}{2}, x = - \frac{5 + 33}{2}

x = \frac{- 5 + 33}{2}, x = - \frac{5 + 33}{2}

Verify Solutions:

x = \frac{- 5 + 33}{2}

True

, x = - \frac{5 + 33}{2}

False

The solution is

x = \frac{- 5 + 33}{2}

ln (9 x + e) = 7

1 - lo g_{3} (8 x + 1) = 5

2 ln (5) + ln (x) - ln (4) = 3

ln (x + 11) + ln (x - 5) = 2 ln (x)

lo g_{x} (49) = 7

What is the answer to log_{10}(5x)+log_{10}(x+5)=1 ?
The answer to log_{10}(5x)+log_{10}(x+5)=1 is x=(-5+sqrt(33))/2
Solve for x: log_{10}(5x)+log_{10}(x+5)=1
The solution is x=(-5+sqrt(33))/2