What is the answer to solvefor x,2x-3y+ln(xy)=4 ?

The answer to solvefor x,2x-3y+ln(xy)=4 is x=(\W(2/(e^{-3y-4)y}))/2

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solvefor x,2x-3y+ln(xy)=4

solve for

x, 2 x - 3 y + ln (x y) = 4

x = \frac{W ( \frac{2}{e ^{- 3 y - 4} y} )}{2}

Solution steps

2 x - 3 y + ln (x y) = 4

Move

2 x

to the right side

- 3 y + ln (x y) = 4 - 2 x

Move

3 y

to the right side

ln (x y) = 4 - 2 x + 3 y

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x y)} = e^{4 - 2 x + 3 y}

Simplify

e^{l n (x y)} : x y

x y = e^{4 - 2 x + 3 y}

Solve

x y = e^{4 - 2 x + 3 y} : x = \frac{W ( \frac{2}{e ^{- 3 y - 4} y} )}{2}

x = \frac{W ( \frac{2}{e ^{- 3 y - 4} y} )}{2}

Verify Solutions:

x = \frac{W ( \frac{2}{e ^{- 3 y - 4} y} )}{2}

True

The solution is

x = \frac{W ( \frac{2}{e ^{- 3 y - 4} y} )}{2}

x, lo g_{e} (x) = - 7

lo g_{5} (x - 3) = - 1

lo g_{3} (x - 3) = 2

ln (6 x + 3) = 5

lo g_{8} (2 x) + lo g_{8} (x - 3) = 1

What is the answer to solvefor x,2x-3y+ln(xy)=4 ?
The answer to solvefor x,2x-3y+ln(xy)=4 is x=(\W(2/(e^{-3y-4)y}))/2