What is the answer to log_{4}(x^2+2x+1)=2 ?

The answer to log_{4}(x^2+2x+1)=2 is x=3,x=-5

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log_{4}(x^2+2x+1)=2

lo g_{4} (x^{2} + 2 x + 1) = 2

x = 3, x = - 5

Solution steps

lo g_{4} (x^{2} + 2 x + 1) = 2

Apply log rules

x^{2} + 2 x + 1 = 16

Solve

x^{2} + 2 x + 1 = 16 : x = 3, x = - 5

x = 3, x = - 5

2^{l o g_{2} (x)} = x

2 lo g_{e} (x + 3) = lo g_{e} (9 x + 19)

lo g_{3} (x) + lo g_{x} (3) = - 2

lo g_{4} (x + 3) = lo g_{4} (9)

lo g_{2} (x^{3}) + lo g_{2} (2) = 4

What is the answer to log_{4}(x^2+2x+1)=2 ?
The answer to log_{4}(x^2+2x+1)=2 is x=3,x=-5
Solve for x: log_{4}(x^2+2x+1)=2
The solution is x=3,x=-5