What is the answer to log_{3}(3x-2)-log_{3}(x+2)=3 ?

The answer to log_{3}(3x-2)-log_{3}(x+2)=3 is No Solution for x\in\mathbb{R}

Solve for x: log_{3}(3x-2)-log_{3}(x+2)=3

The solution is No Solution for x\in\mathbb{R}

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lo g_{3} (3 x - 2) - lo g_{3} (x + 2) = 3

No Solution for x \in R

Solution steps

lo g_{3} (3 x - 2) - lo g_{3} (x + 2) = 3

Add

lo g_{3} (x + 2)

to both sides

lo g_{3} (3 x - 2) - lo g_{3} (x + 2) + lo g_{3} (x + 2) = 3 + lo g_{3} (x + 2)

Simplify

lo g_{3} (3 x - 2) = 3 + lo g_{3} (x + 2)

Apply log rules

3 x - 2 = 27 (x + 2)

Solve

3 x - 2 = 27 (x + 2) : x = - \frac{7}{3}

x = - \frac{7}{3}

Verify Solutions:

x = - \frac{7}{3}

False

The solution is

No Solution for x \in R

6 (ln (4 x) + 1) = 0

ln (5 - 2 x) = 3

2 lo g_{3} (x) = lo g_{10} (x^{2})

ln (3 ln (x)) = 0

lo g_{4} (n + 1) - lo g_{4} (n - 2) = 1

What is the answer to log_{3}(3x-2)-log_{3}(x+2)=3 ?
The answer to log_{3}(3x-2)-log_{3}(x+2)=3 is No Solution for x\in\mathbb{R}
Solve for x: log_{3}(3x-2)-log_{3}(x+2)=3
The solution is No Solution for x\in\mathbb{R}