What are the solutions to the equation 2(x+7)^2=64 ?

The solutions to the equation 2(x+7)^2=64 are x=4sqrt(2)-7,x=-4sqrt(2)-7

Find the zeros of 2(x+7)^2=64

The zeros of 2(x+7)^2=64 are x=4sqrt(2)-7,x=-4sqrt(2)-7

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2 (x + 7)^{2} = 64

x = 42 - 7, x = - 42 - 7

Decimal Notation

x = - 1.34314 \dots, x = - 12.65685 \dots

Solution steps

2 (x + 7)^{2} = 64

Divide both sides by

2

(x + 7)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 32 : x = 42 - 7

Solve

x + 7 = - 32 : x = - 42 - 7

The solutions to the quadratic equation are:

x = 42 - 7, x = - 42 - 7

5 (4)^{4}

(- \frac{3}{4})^{- 2}

\frac{7}{9} - \frac{2}{3}

5 x - 7 = 3

9 m^{2} - 64

What are the solutions to the equation 2(x+7)^2=64 ?
The solutions to the equation 2(x+7)^2=64 are x=4sqrt(2)-7,x=-4sqrt(2)-7
Find the zeros of 2(x+7)^2=64
The zeros of 2(x+7)^2=64 are x=4sqrt(2)-7,x=-4sqrt(2)-7