What is the answer to log_{2}(4x+9)=4 ?

The answer to log_{2}(4x+9)=4 is x= 7/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(4x+9)=4

lo g_{2} (4 x + 9) = 4

x = \frac{7}{4}

Solution steps

lo g_{2} (4 x + 9) = 4

Apply log rules

4 x + 9 = 16

Solve

4 x + 9 = 16 : x = \frac{7}{4}

x = \frac{7}{4}

lo g_{2} (x) + lo g_{8} (x) = 8

lo g_{7} (7 x - 3) = lo g_{7} (5 x + 15)

ln (x - 1) + (\frac{1}{( 2 x - 2 )}) = c

x, ln (x) = 5 k

lo g_{10} (x^{2} - 21 x) = 1