What is the answer to log_{x+1}(x^2+2x-1)=2 ?

The answer to log_{x+1}(x^2+2x-1)=2 is No Solution for x\in\mathbb{R}

Solve for x: log_{x+1}(x^2+2x-1)=2

The solution is No Solution for x\in\mathbb{R}

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lo g_{x + 1} (x^{2} + 2 x - 1) = 2

No Solution for x \in R

Solution steps

lo g_{x + 1} (x^{2} + 2 x - 1) = 2

Apply log rules

\frac{ln ( x ^{2} + 2 x - 1 )}{ln ( x + 1 )} = 2

Multiply both sides by

ln (x + 1)

\frac{ln ( x ^{2} + 2 x - 1 )}{ln ( x + 1 )} ln (x + 1) = 2 ln (x + 1)

Simplify

ln (x^{2} + 2 x - 1) = 2 ln (x + 1)

Apply log rules

x^{2} + 2 x - 1 = (x + 1)^{2}

Solve

x^{2} + 2 x - 1 = (x + 1)^{2} :

No Solution

No Solution for x \in R

x, y - 2 = ln (x + e^{2})

lo g_{2} (x) - 3 lo g_{2} (x) = 6

lo g_{x} (2) = 0

lo g_{x} (2) = 5

3 + 2 ln (x^{2}) = 7

What is the answer to log_{x+1}(x^2+2x-1)=2 ?
The answer to log_{x+1}(x^2+2x-1)=2 is No Solution for x\in\mathbb{R}
Solve for x: log_{x+1}(x^2+2x-1)=2
The solution is No Solution for x\in\mathbb{R}