What is the answer to log_{10}(x)=1+log_{3}(x) ?

The answer to log_{10}(x)=1+log_{3}(x) is x=10^{(log_{10}(3))/(log_{10)(3)-1}}

Solve for x: log_{10}(x)=1+log_{3}(x)

The solution is x=10^{(log_{10}(3))/(log_{10)(3)-1}}

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lo g_{10} (x) = 1 + lo g_{3} (x)

x = 1 0^{\frac{l o g _{10} ( 3 )}{l o g _{10} ( 3 ) - 1}}

Solution steps

lo g_{10} (x) = 1 + lo g_{3} (x)

Apply log rules

x = 1 0^{\frac{l o g _{10} ( 3 )}{l o g _{10} ( 3 ) - 1}}

Verify Solutions:

x = 1 0^{\frac{l o g _{10} ( 3 )}{l o g _{10} ( 3 ) - 1}}

True

The solution is

x = 1 0^{\frac{l o g _{10} ( 3 )}{l o g _{10} ( 3 ) - 1}}

lo g_{2} (x) = - 7

2 ln (x) + ln (x + 1) = ln (2)

lo g_{2} (x) = 20

ln (d) = ln (x) + 1

lo g_{6} (x) = 2 - lo g_{6} (x - 5)

What is the answer to log_{10}(x)=1+log_{3}(x) ?
The answer to log_{10}(x)=1+log_{3}(x) is x=10^{(log_{10}(3))/(log_{10)(3)-1}}
Solve for x: log_{10}(x)=1+log_{3}(x)
The solution is x=10^{(log_{10}(3))/(log_{10)(3)-1}}