What is the answer to 0.2=-log_{10}(x) ?

The answer to 0.2=-log_{10}(x) is x= 1/(10^{0.2)}

Solve for x: 0.2=-log_{10}(x)

The solution is x= 1/(10^{0.2)}

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0.2 = - lo g_{10} (x)

x = \frac{1}{1 0 ^{0.2}}

Decimal Notation

x = 0.63095 \dots

Solution steps

0.2 = - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

0.2 + lo g_{10} (x) = 0

Move

0.2

to the right side

lo g_{10} (x) = - 0.2

Apply log rules

x = \frac{1}{1 0 ^{0.2}}

Verify Solutions:

x = \frac{1}{1 0 ^{0.2}}

True

The solution is

x = \frac{1}{1 0 ^{0.2}}

lo g_{2} (11 - x) = lo g_{2} (x + 1) + 3

lo g_{a} (N) = ln (x)

lo g_{3} (2 x) = 1

lo g_{x} (2 x + 1) = - 1

x, ln (x + y - 5) = 0

What is the answer to 0.2=-log_{10}(x) ?
The answer to 0.2=-log_{10}(x) is x= 1/(10^{0.2)}
Solve for x: 0.2=-log_{10}(x)
The solution is x= 1/(10^{0.2)}