What is the answer to log_{32}(4)=log_{2}(x) ?

The answer to log_{32}(4)=log_{2}(x) is x=2^{2/5}

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log_{32}(4)=log_{2}(x)

lo g_{32} (4) = lo g_{2} (x)

x = 2^{\frac{2}{5}}

Solution steps

lo g_{32} (4) = lo g_{2} (x)

Apply log rules

2^{\frac{2}{5}} = x

Switch sides

x = 2^{\frac{2}{5}}

Verify Solutions:

x = 2^{\frac{2}{5}}

True

The solution is

x = 2^{\frac{2}{5}}

lo g_{3} (x) = \frac{3}{2}

lo g_{16} (X) = \frac{3}{4}

4.35 = - lo g_{10} (x)

x, ln (y - 1) = ln (x + 3) + c

1 - ln (x - 1) = 0

What is the answer to log_{32}(4)=log_{2}(x) ?
The answer to log_{32}(4)=log_{2}(x) is x=2^{2/5}
Solve for x: log_{32}(4)=log_{2}(x)
The solution is x=2^{2/5}