What is the answer to log_{10}(x)+log_{10}(x+5)=4 ?

The answer to log_{10}(x)+log_{10}(x+5)=4 is x=(-5+5sqrt(1601))/2

Solve for x: log_{10}(x)+log_{10}(x+5)=4

The solution is x=(-5+5sqrt(1601))/2

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lo g_{10} (x) + lo g_{10} (x + 5) = 4

x = \frac{- 5 + 5 1601}{2}

Solution steps

lo g_{10} (x) + lo g_{10} (x + 5) = 4

Apply log rules

x (x + 5) = 10000

Solve

x (x + 5) = 10000 : x = \frac{- 5 + 5 1601}{2}, x = \frac{- 5 - 5 1601}{2}

x = \frac{- 5 + 5 1601}{2}, x = \frac{- 5 - 5 1601}{2}

Verify Solutions:

x = \frac{- 5 + 5 1601}{2}

True

, x = \frac{- 5 - 5 1601}{2}

False

The solution is

x = \frac{- 5 + 5 1601}{2}

lo g_{10} (x) = 11.2

lo g_{10} (4 x + 8) = 2

2 + 3 ln (x) = 8

ln (x - 1) = 2 \cdot ln (x)

3 = lo g_{6} (x)

What is the answer to log_{10}(x)+log_{10}(x+5)=4 ?
The answer to log_{10}(x)+log_{10}(x+5)=4 is x=(-5+5sqrt(1601))/2
Solve for x: log_{10}(x)+log_{10}(x+5)=4
The solution is x=(-5+5sqrt(1601))/2