What is the answer to log_{4}(x-6)+log_{4}(2)=2 ?

The answer to log_{4}(x-6)+log_{4}(2)=2 is x=14

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log_{4}(x-6)+log_{4}(2)=2

lo g_{4} (x - 6) + lo g_{4} (2) = 2

x = 14

Solution steps

lo g_{4} (x - 6) + lo g_{4} (2) = 2

Move

lo g_{4} (2)

to the right side

lo g_{4} (x - 6) = 2 - lo g_{4} (2)

Apply log rules

x - 6 = 4^{2 - \frac{1}{2}}

Solve

x - 6 = 4^{2 - \frac{1}{2}} : x = 14

x = 14

Verify Solutions:

x = 14

True

The solution is

x = 14

lo g_{2} (x + 5) = 4

lo g_{8} (x) = \frac{- 2}{3}

ln (x) + ln (x - 6) = ln (7 x)

lo g_{5} (x) = 1 + lo g_{5} (x - 4)

lo g_{3} (3 0^{x} - 9) = 0

What is the answer to log_{4}(x-6)+log_{4}(2)=2 ?
The answer to log_{4}(x-6)+log_{4}(2)=2 is x=14
Solve for x: log_{4}(x-6)+log_{4}(2)=2
The solution is x=14