What is the answer to 4+log_{2}(9k)=2 ?

The answer to 4+log_{2}(9k)=2 is k= 1/36

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4+log_{2}(9k)=2

4 + lo g_{2} (9 k) = 2

k = \frac{1}{36}

Decimal Notation

k = 0.02777 \dots

Solution steps

4 + lo g_{2} (9 k) = 2

Move

4

to the right side

lo g_{2} (9 k) = - 2

Apply log rules

9 k = \frac{1}{4}

Solve

9 k = \frac{1}{4} : k = \frac{1}{36}

k = \frac{1}{36}

Verify Solutions:

k = \frac{1}{36}

True

The solution is

k = \frac{1}{36}

x, ln (1 - y^{2} - x) = 0

17 ln (x) = 11

lo g_{5} (x + 7) = lo g_{5} (2 x + 3)

lo g_{3} (x + 3) - lo g_{3} (x - 5) = 2

x = e^{\frac{l n ( x )}{x}}

What is the answer to 4+log_{2}(9k)=2 ?
The answer to 4+log_{2}(9k)=2 is k= 1/36
Solve for k: 4+log_{2}(9k)=2
The solution is k= 1/36